This question was previously asked in

Territorial Army Paper I : Official Practice Test Paper - 1

Option 1 : \(11 \dfrac{1}{9}\%\)

**Given**

If the income of Ram is \(12 \dfrac{1}{2}\%\) more than that of Shyam

**Calculation**

\(12 \dfrac{1}{2}\%\) = \(\frac{{25}}{{200}} = \frac{1}{8}\)

AS per the question

Ram : Shyam = 9 : 8

Income of shyam is less than that of Ram

9 - 8 = 1 unit

⇒ 1/9 × 100 = \(11 \dfrac{1}{9}\%\)